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PROBLEM ON AGES
Dear students in the series of study notes
this week our topic is Problems based on
ages which is a sub topic of Ratio and
proportion means we will use all logic and
shortcuts what we studied in that chapter.
So lets start…
If the current age of a person be X, then
– age after n years = X + n
– age n years ago = X – n
– n times the age = nX
– If ages in the numerical are mentioned in
ratio A : B, then A : B will be AX and BX
Students frankly speaking there is no basic
in this chapter so we will learn through
questions so lets start
Q.1. The age of the father 3 years ago was 7
times the age of his son. At present, the
father’s age is five times that of his son.
What are the present ages of the father and
the son?
Solution:
Let the present age of son = x years
Then, the present age of father = 5xyr
3 years ago,
7(x – 3)= 5x – 3
Or, 7x – 21 =5x – 3
Or, 2x =18
x = 9 years.
Therefore, son’s age = 9 years
Father’s age = 45 years
Short tricks:-
Son’s age =
7 1 3 9
7 5
years
And father’s age = 9 × 5 = 45 years.
Q.2. At present, the age of the father is five
times the age of his son. Three years hence,
the father’s age would be four times that of
his son. Find the present ages of the father
and the son.
Solution:
Let the present age of son = x years
Then, the present age of father = 5x years
3 years hence,
4(x+3)= 5x+3
Or, 4x + 12=5x +3
x= 9years.
Therefore, son’s age = 9 years and father’s
age = 45 years
Short tricks :
Son’s age = {3×(4-1)/5-4} = 9 years
father’s age = 9 × 5 =45 years
Q.3. Three years earlier, the father was 7 times
as old as his son. Three years hence, the
father’s age would be four times of his son.
What are the present ages of the father and
the son?
Solution:
Let the present age of son = x years and the
present age of father = y years
3 years earlier, 7(x – 3) = y – 3
7x – y =18………….(i)
3 yes hence, 4(x+3) = y +3
4x +12 = y + 3
4x – y = – 9 …………(ii)
Solving (1) & (2) we get, x = 9 years & y
= 45 years
Short tricks :
Son’s age = {3×(4-1)+3(7-1)}/(7-4) = 9
years
Q.4. The sum of the ages of a mother and her
daughter is 50 years. Also 5 years ago, the
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mother’s age was 7 times the age of the
daughter. What are the present ages of the
mother and the daughter?
Solution:
Let the age of the daughter be x years.
Then, the age of the mother is (50x – x)
years
5 years ago, 7(x – 5) = 50 – x – 5
Or, 8x = 50 – 5 +35 = 80
x =10
Therefore, daughter’s age = 10 years and
mother’s age = 40years
Short tricks :
7 1 50 5 10
7 1
years
Thus, daughter’s age = 10 years and
mother’s age = 40 years
Q.5. The sum of the ages of a son and father is
56 years. After 4 years, the age of the father
will be three times that of the son. What is
the age of the son?
Solution:
Let the age of the son be x years.
Then, the age of the father is (56 – x) years.
After 4 years, 3(x+4) = 56 – x +4
Or, 4x =56 +4 – 12 = 48
x = 12 years
Thus, son’s age = 12 years.
Short tricks : {56 -4(3-1)}/(3+1)
= 12 years
Q.6. The present age of the father is 5 times the
age of his son. Five years ago, the age of
the Father was ten times the age of his son
at that time. How old is the father at
present?
(1) 45 years (2) 40 years
(3) 48 years (4) 49 years
(5) None of these
Regular Method to solve Age Problem
Solution:
Step 1:
Let us assume father’s present age as F
Let us assume the present age of the son to
be as S
Step 2:
As mentioned in the question, the present
age of the father is 5 times the age of son
F = 5×S (i)
Step 3:
Now frame an equation now
( F – 5 ) = 10 ( S – 5) (ii)
Step 4:
F – 5 = 10S – 50
5S – 5 = 10S – 50
5S = 45
S =9
F = 9×5 = 45
SMART METHOD TO SOLVE AGE
PROBLEMS
Step 1:
To solve this question using the smart
method, we need to understand the question
carefully.
As mentioned in the question that the
father’s age is 5 times the age of son, we
can clearly make out that the father’s age
should be a multiple of 5.
By this, we can easily eliminate the options
which are not the multiples of 5.
Therefore, option 3 and option 4 are
eliminated.
Step 2:
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Now we take the second condition into
consideration and check which option
satisfies the condition.
Option 1: 45 years.
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If the father’s present age is 45 then the
son’s age would be 9, since the father is 5
times the son’s age.
Now, five years ago father’s age would be
40 and son’s age would be 4.
Hence, the second statement states that 5
years ago father’s age was 10 times the age
of the son.
As, 40 = 10 x 4; option 1 satisfies both the
condition.
Therefore the father’s present age is 45.
Question: Father’s age is 25 years more
than the son’s age. Four years hence,
Fathers age will become 1 less than thrice
the son’s age
What is father’s present age?
(1) 31 (2) 38 (3) 34
(4) 36 (5) None of these
Regular Method to solve Age Problems
Solution:
Step 1:
Let us assume father’s present age to be as
‘F.’
Let us assume son’s present age to be as
‘S.’
As mentioned in the question father’s age is
25 years more than the son’s age.
F = S + 25 (i)
Step 2:
After 4 years,
Father’s age = F + 4
Son’s age = S + 4
Father’s age is 1 less than the thrice of
son’s age
F + 4 = 3 (S + 4) – 1 (ii)
Step 3:
By substituting equation (i) in equation (ii)
we get that,
F + 4 = 3 (F – 25 + 4) – 1
F + 4 = 3F – 63 – 1
2F = 68
F = 34 years.
Therefore, Father’s present age is 34 years.
1. The ratio of A’s age 3 years ago and B’s
age 5 years ago is 4:5. If A is 4 years
younger than B then what is the present age
of B?
Solution:
Approach 1: Let assume at present A’s age
is X and B’s age is Y.
Given, (X-3):(Y-5) = 4:5 and X = Y-4
Solve both equations and then get X and Y.
Now, we have to equations and two
variables. Generally, this type of approach
consumes more time and is not preferable.
Approach 2: In this type of question,
assume only one variable i.e. called base
variable. Let A’s present age is X, then B’s
present age is X+4. Students often commit
silly mistakes, they tick the option which
have X value but present age of B is asked
in question.
So, (A’s 3 years ago):(B’s 5 years ago) =
4:5
(X-3): (X+4-5) = 4:5
(X-3): (X-1) = 4:5
5X-15 = 4X-4
X= 11 i.e. A’s Present age
and B’s present age is X+4 = 11+4 = 15
years.
2. A is 3 years older than B while B is 2 years
older than C. The ratio of age of A 4 years
hence and B 3years ago is 5:3. What was
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the age of C 6 years ago?
Solution:
There are three variables in this question
and students are often confused about
which variables should be assumed as base
variable. You can see in question relation
of B with both A and C is mentioned. So,
you can assume B as base variable. If you
assume another one as base variable, there
is a chance that calculation may become a
little harder.
Let present age of B’s is X, then A’s age =
X+3 and C’s age = X-2
(Age of A 4 years hence): (Age of B 4
years ago) = 5:3
(X+3+4): (X-3) = 5:3
(X+7): (X-3) = 5:3
3X+21 = 5X-15
2X = 36
X = 18
present age of C is X-2 = 18-2 = 16 years
age of C 6 years ago = 16-6 = 10 years
Shortcut: (X+7): (X-3) = 5:3
difference of 5 and 3 is directly
proportional to difference of
(X+7) and (X-3)
So,(5-3) ∝ (X+7)-(X-3)
2 ∝ 10
1 ∝ 5
We can write X+7 = 5×5 , X = 18
Hence, age of C 6 years ago = 10 years
3. The average age of Atul, Jatin and Sonu is
24years. 2 year ago, average age of Atul
and Sonu was 23years. 2years hence
average age of Jatin and Sonu is 26 years.
Find the present age of Sonu?
Solution:
Given, average age of Atul, Jatin and Sonu
= 24 years
∴ total age of Atul, Jatin and Sonu = 24×3
= 72 years ….(1)
2 years ago, average age of Atul and Sonu
= 23
2 years ago, total age of Atul and Sonu =
46
∴ present total age of Atul and Sonu = 50
….(2)
2 years hence, average age of Jatin and
Sonu = 26
2 years hence, total age of Jatin and Sonu =
52
∴ present total age of Jatin and Sonu = 48
…….(3)
From equation 1, 2 and 3
Present age of Sonu is 26 years.
4. The average age of A and B is 25 years. If
C were to replace A, the average would be
24 and if C were to replace B, the average
would be 26. What are the ages of A, B and
C respectively?
Solution: Given, avg. of (A+B) = 25
∴ (A+B) = 50
Avg. of (C+B) = 24
∴ (C+B) = 48
Avg. of (A+C) = 26
∴ (A+C) = 52
Now, A+B+C = (50+48+52)/2
A+B+C = 75
C = 25, A = 27, B = 23
5. The ages of Sona and Mona are in the ratio
of 15:17 respectively. After 6 years, the
ratio of their ages will be 9:10. What will
be the age of Mona after 6 years?
Solution: Let present age of Sona is 15X,
then Mona = 17X
Given, (15X+6) : (17X+6) = 9 : 10
150X+60 = 153X+54
3X = 6
X = 2 years
Age of Mona after 6 years is (17×2+6)
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= 40 years.
Now, we will discuss questions which are
asked by some of our students.
1. The present ages of A,B and C in
proportion 4:7:9, eight years ago, the sum
of their ages was 56. find their respective
ages (in years)
Solution:
Let ratio of present ages of A,B and C is
4x:7x:9x
sum of their ages eight years ago = 56
(4x-8)+(7x-8)+(9x-8) = 56
20x = 80
x = 4
A = 4x = 16 years
B = 7x = 28 years
C = 9x = 36 years
2. he sum of the ages of Rinku and Gopal is
40 years. 5 years hence ratio of their ages
will be 3:7. Find the age of Rinku?
Solution:
Given 5years hence ratio of ages of Rinku
and Gopal is 3:7
let 5years hence, age of Rinku = 3X and
Gopal = 7X
So, present age of Rinku = 3X-5 and Gopal
= 7x-5
Sum of present ages of Rinku and Gopal
= 40
(3X-5)+(7X-5) = 40
10X = 50
X = 5
present age of Rinku = 3X-5 = 10years
3. The present age of Romila is one-fourth
that of her father. After 6 years the father’s
age will be twice the age of Kapil. If Kapil
celebrated fifth birthday 8 years ago. What
is Romila’s present age?
Solution:
Let present age of Romila is X, then
Father’s age = 4X
6 years hence,
father’s age = 4X+6
2 (Age of Kapil) = 4X+6
Age of Kapil = 2X+3
Present age of Kapil = 2X+3-6 = 2X-3
Kapil celebrated his 5th bairthday 8 years
ago
So, Present age of Kapil is 5+8 = 13 years
2X-3 = 13
2X = 16
X = 8years.
Shortcut approach: Kapil celebrated his 5th
birthday 8 years ago.
Present age of Kapil = 13
After 6years, father’s age will be twice of
the Kapil.
2x(13+6) = 4X+6
X= 8 years
4. A man’s age is 133(1/3)% of what it was 8
years ago, but 80% of what it will be after 8
years. What is his present age?
Solution:
Let the present age be X years.
Then 133(1/3)% of (X-8) = X and
80%(X+8) = X
So, 133(1/3)% of (X-8) = 80%(X+8)
4(X-8)/3 = 4(X+8)/5
5(X-8) = 3(X+8)
2X = 64
X = 32
Shortcut: You don’t need to solve both
equation. Solve any equation you will get
the answer.
133(1/3)% of (X-8) = X
4(X-8)/3 = X
4X-32 = 3X
X = 32 years
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SOLVED EXERCISE
Q.1. Difference between ages of Raman and
Preet is 16 years. If Raman‘s age ten years
hence will be two times the age of Preet,
find Raman‘s age.
R – P = 16
(R + 10) = 2P
Solve, R = 42
Q.2. When a couple was married, their average
age was 22 years. When their first child
was born, the average age of all the three
became16 years. When their second child
was born, the average of all 4 became 15
years. Find the average age of couple at the
time when their second child was born.
At the time of marriage total age of
couple=44
when 1st child is born total age of
three=16×3=48
Difference=48-44=4 years (Child is of 0
years hence this is the sum of age increase
of couple)
When second child is born sum of
age=4×15=60 years
=> increase of 12 years after first child,
means age of husband, wife and first child
increased by 4 years each. SO increase in
husband and wife
total age = 8 years total increase =4+8=12
total age=44+12=56; average=56/2=28
years
Q.3. The average age of a group of 20 men is 22
years. If two men whose age are 24 and 31
years respectively join the group, the
average age of new group increase or
decrease by
When 2 new people join if the sum of their
age is 44 then the average will not change,
but the sum of age of new people is 55 i.e
increase of 11
hence avg increases by 11/22=0.5 years.
Q.4. The ratio of present age of Tiya and Piya is
3 : 5 and the ratio of ages of Tiya 5 years
ago and Piya 5 years hence is 1 : 3. Find the
present age of Piya.
T/P=3/5 ——- (i)
T-5/P+5 =1/3 ———- (ii)
Solve and get
T=15 years
P= 25 years
Q.5. 10 years ago daughter‘s age was two-fifth
of her mother‘s age that time. While 10
years hence her age will be three-fifth of
her mother‘s age then. Find the difference
in the ages of the two.
(x-10) = 2/5 (y-10)
(x+10) = 3/5 (y+10)
Solve, x = 26 and y = 50
Q.6. A person‘s present age is two-ninth of the
age of his mother. After 10 years, he will
be four-eleventh of the age of his mother.
How old is the mother after 15 years?
Present ratio P:M ==>2:9
After 10years P:M=4:11
Then (2x+10)/(9x+10) = 4/11
22x+110=36x+40
X=5.
Then Mother‘s present age=9×5=45 years.
After 15 years Mother‘s age is=60 years.
Q.7. Ratio of the ages of A and B is 5 : x. A is
18 years younger to C. After nine years C
will be 47 years old. If the difference
between the ages of A and B is same as the
age of C, what is the value of x?
A:B=5:x –1
A = C – 18 —2
C + 9 = 47 =>C=47-9=38 years.
A – B = C —3
From 2 A=38-18=20 years.
From 1 20/B=5/x==> B=4x
From 3 4x-20=38
X=14.5.
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Q.8. Ratio of present age of A and B is 7 : 9 and
ratio of ages of A 5 years back and age of B
5 years later is 3:5. Find the present age of
B.
A/B=7/9
(A-5)/(B+5)=3/5
solve both and get A=35 and B=45
Q.9. The present age of a son is 40% of his
father age. And the age of his mother is
220% of his age. The average age of three
members is 38. Find the present age of
mother.
Son= 40% of father.
F:S=5:2
Mother=220% of son=11/5
M:S=11:5
make F:M:S =25:22:10
avg=(25+22+10)/3=19
19=38
1=2
=>22=44
Q.10. Rama got married 8 years ago. Her present
age is 1 (1/3) times of her age at the time of
marriage. She has a son who is one eighth
of her present age. Then find the age of her
son.
1 (1/3)=4/3
Ratio of present age of Rama and her age
at time of marriage=4:3 ——– difference
=1
1=8 years
4=32
age of son=32/8=4 years
Q.11. The fathers age is four times as much as the
sum of the age of his three children but 6
years hence his age will be thrice as the
sum of their age. The present age of father
is?
Let sum of children age=x ;
hence father =4x (4x+6)/x+6 = 3/1
x=12; father=48
Q.12. In a class of 20 students the average of all
the students is 18 years. If the age of their
teacher is added then the average becomes
19 years. Find the age of teacher after 5
year.
Let age of teacher=x
(total age)/ total people=19
360+x/21=19
x=39
hence age after 5 years=44
Q.13. The average age of a couple at the time of
their marriage was 22. Two years after the
marriage their child was born. Now he is 4
years old. Find the average age of their
present age.
Sum of couples age at time of
marriage=2×22=44
when son was born, total age=44+2+2=48
After 4 years total age=48+4+4+4=60
avg=60/3=20
Q.14. The present age of Sumit is 1/8th of his
father. After 4 years, the father‘s age will
be twice the age of Raman. If Raman
celebrated his 6th birthday eight years ago,
what is Sumit‘s present age?
Present ratio Sumit : Father is 1 :
8……………. (1)
4 years after, Father : Raman is 2 :
1………………..(2)
Raman‘s 6th birthday was 8 years ago, so
after 4 years he will be 18 years old
Put in equation (2), Raman = 18, Father =
36
So present age of father = 32
So of Sumit is 32/8 = 4 years
Q.15. Sheetal‘s age at the time of her marriage
was 4/5th of her present age. If she married
6 years ago and now she has a son who is
1/10th of her present age, then find the age
of her son 5 years hence.
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4/5 × 6 = 24/30
24 => at the time of marriage
30 years => now
Son = 1/10 of present age = 1/10 × 30 = 3
years
5 years hence = 3+5 = 8 years
Q.16. Ram is 6 years elder then his brother and 5
years younger than her sister Sheena. When
Sheena was born, her father‘s age was 24
and when Ram‘s brother was born his
mother‘s age was 29. Find the difference
between ages of Ram‘s father and his
mother.
Bother=x
Ram=x+6
Sheena=x+11
Father=x+11+24=x+35
Mother=x+29
Difference=x+35 –(x+29)=6 years
Q.17. If 6 years are subtracted from the present
age of Babita and the remainder is divided
by 18, then the present age of her
granddaughter Geeta is obtained. If Geeta
is 2 years younger to Sita whose age is 5
years, then what is Babita‘s present age?
Geeta‘s age = (5-2) = 3 years
Let age of Babita = x years
So (x-6)/18 = 3
Solve, x = 60
Q.18. A‘s age is twice C‘ age. Ratio of age of B 2
years hence to age of C 2 years ago is 5 : 2.
C is 14 years younger than D. Difference in
ages of D and A is 4 years. Find the
average of their ages.
A = 2C
(B+2)/(C-2) = 5/2
C = D – 14
D – A = 4
Solve, A = 20, B = 18, C = 10, D = 24
Q.19. Ratio of ages of A 5 years hence to B‘s age
3 years ago is 5 : 3. Also ratio of ages of A
4 years ago to B‘s age 2 years hence is 4 :
5. Find the age of the elder.
(A+5)/(B-3) = 5/3
(A-4)/(B+2) = 4/5
Solve A = 20, B = 18
Q.20. The respective ratio between the present
ages of father, mother and daughter is 7
: 6 : 2. The difference between mother’s
and the daughter’s age is 24 years. What
is the father’s age at present?
Let the common ratio be x
∴ The percentages of father’s, mother’s
and daughter’s are 7x, 6x, 2x
respectively.
According to the question
6x ⎯ 2x = 24
4x = 24
x = 6
∴ father’s present age = 7 × 6 = 42 years
Q.21. The average age of 9 students and their
teacher is 16 year. The average age of
the first four students is 19 years and
that of the last five is 10 years. Find the
age of the teacher.
Sum of the age of 10 persons (9
students + 1 teacher)=10 × 16 = 160
years
Sum of age of first 4 students = 4 × 19
= 76 years
Sum of ages of last 5 students= 5×10
= 50 years
Hence, the age of teacher will be
= (Sum of age of all 10 persons) – (sum
of age of 9 students)
= 160 – (76 + 50)= 34 years` (Ans)
Sum of the ages of Nitika and Kruti
= 21 x 2 = 42 years
Ratio of Nitika : Kruti = 4 : 3
Kruti’s age
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Q.22. The ratio of the present ages of Jyoti
and Amit is 8 : 9 After four years Jyoti’s
age will be 28 year What was Amit’s
age 8 years ago?
Let X and y are the present ages of Jyoti
and Amit respectively.
Hence X:Y = 8:9 ⇒ X/Y = 8/9
⇒ Y = 9X/8
Four years ago Jyoti’s age = 28 ⇒ X + 4
= 28 ⇒ X = 24 years
Hence Y = 9 × 24 /8 = 9 × 3 =27 years.
Amit’s age 8 years ago = 27 – 8 = 19
years
Q.23. At present, the ratio of the ages of Maya
and Chhaya is 6 : 5 and fifteen years
from now, the ratio will get changed to
9 : 8. Maya’s present age is
Let Maya’s and Chhaya’s present ages
be 6x and 5x respectively.
After 15 years,
Maya’s age = (6x + 15) years
Chhaya’s age = (5x + 15) years
Therefore,
8(6x + 15) = 9(5x + 15)
48x + 120 = 45x + 135
48x – 45x = 135 – 120
3x = 15
x = 5
∴ Maya’s present age = 6 × 5 = 30
years
Hence, option C is correct.
Q.24. I am three times as old as my son
15years hence, I will be twice as old as
my son. The sum of our ages is
Let son’s present age = x years
∴ My age = 3x years
15 years hence,
Son’s age = (x + 15) years
My age = (3x + 15) years
Therefore, (3x + 15) = 2(x + 15)
3x – 2x = 30 – 15
x = 15
∴ son’s present age = 15 years
My age = 15 × 3 = 45 years
The required sum of their ages = 15 +
45 = 60 years
Hence, option B is correct.
Q.25. The ratio of the present ages of Tarun
and Varun is 3 : 7. After 4 years
Varun’s age will be 39 years. What was
Tarun’s age 4 years ago?
Varun’s present age = 39 – 4 = 35 years
So, Tarun’s present age = 15 years
Tarun’s age 4 years ago = 11 years
Q.26. The present age of Suraj is six times the
age of Vijay. Also, Vijay’s present age
is 20 years less than Suraj’s age. What
is Suraj’s present age?
Vijay’s present age = X years
Suraj’s present age = years
Suraj’s present age = years
Q.27. Ages of A and B are in the ratio of 2 : 3
respectively. 6 yr hence the ratio of
their ages will become 8 : 11
respectively. What is B’s present age?
Let the age of A is and that of B is y
Acc. to question,
. x 2
y 3
3x-2y=0 …….(I)
According to the second condition,
x 6 8
y 6 11
………(II)
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On solving Eqs. (i) and (ii), we get
x=18 and y=27
So, the age of B = 27 yr
PRACTICE EXERCISE
Q.1. The present ratio of age of A and B is 3 : 5 .
If the sum of present age of A and B is 48
years. Find the age of B before 5 years ?
Q.2. The present ratio of age of A and B is 3 : 5 .
If the sum of present age of A and B is 48
years. Find the age of B before 5 years ?
Q.3. A man’s age is 125% of what it was 10
years ago, but 83 1
3
%of what it will be after
10 years. What is his present age?
Q.4. Father is aged three times more than his son
Sunil. After 8 years, he would be two and a
half times of Sunil’s age. After further 16
years, how many times would he be of
Sunil’s age?
Q.5. A father said to his son, “I was as old as
you are at the present at the time of your
birth”. If the father’s age is 38 years now,
what was the son’s age five years back?
Q.6. A person‘s present age is two-ninth of the
age of his mother. After 10 years, he will
be four-eleventh of the age of his mother.
How old will be her mother after 15 years?
Q.7. Ratio of the ages of A and B is 5 : x. A is
18 years younger to C. After nine years C
will be 47 years old. If the difference
between the ages of A and B is same as the
age of C, what is the value of x?
Q.8. 16 years ago, my Uncle was 8 times more
older than me. After 8 years from today,
my uncle will be thrice as old as I will be at
that time. Eight years ago, what was the
ratio of my age and my uncle‘s age?
Q.9. If Sita’s mother was 4 times as old as Sita
10 year ago. After ten years mother will be
twice as old as Sita. How old is Sita’s
mother at present ?
Q.10. Jayesh is as more younger to Amit as
Jayesh is older to Prashant. If the sum of
the ages of Amit and Prashant is 48 years.
What is the age of Amit in years ?
Q.11. Ram got married 10 years ago. His present
age is 11
3
times of age at the time of
marriage. Ram’s sister was 4 year youngers
to him at the time of his marriage. Find out
the present age of Ram’s sister?
Q.12. If the two digits of the age of Arun are
reversed then the new age so obtained is the
age of his wife. 1/11 part of the sum of
their ages is equal to the difference between
their ages. If Arun is older than his wife
then find the difference between their ages?
Q.13. Gaurav’s brother is 3 years elder to him.
His father was 28 years of age when his
sister was born while his mother was 26
years of age when he was born. If his sister
was 4 years of age when his brother was
born, the ages of Gaurav’s father when his
brother was born ?
Q.14. A man’s age is 125% of what it was 10
years ago, but 83 1
3
% of what it will be
after 10 years. What is his present age?
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Q.15. Father age is three times as his son Sunil.
After 8 years, he would be two and a half
times of Sunil’s age. After 16 years, how
many times would he be of Sunil’s age?
Q.16. A father said to his son, “I was as old at the
time of your birth as you are at the present
“. If the father’s age is 38 years now, what
was the son’s age five years back?
Q.17. A person‘s present age is 2
9
of the age of
his mother. After 10 years, he will be 4
11
of
the age of his mother. How old will be her
mother after 15 years?
Q.18. Ratio of the ages of A and B is 5 : x. A is
18 years younger to C. After nine years C
will be 47 years old. If the difference
between the ages of A and B is same as the
age of C, what is the value of x?
Q.19. 16 years ago, my uncle was 8 times more as
old as I was . After 8 years from today, my
uncle will be thrice as old as I will be at
that time. Eight years ago, what was the
ratio of my age and my uncle‘s age?
Q.20. Jayesh is as younger than Amit as he is
older than Prashant. If the sum of the ages
of Amit and Prashant is 48 years. What is
the age of Amit in years ?
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